3x(x-3)=(7x^2-10x)

Solution for 3x(x-3)=(7x^2-10x) equation:

3x(x-3)=(7x^2-10x)

We move all terms to the left:

3x(x-3)-((7x^2-10x))=0

We multiply parentheses

3x^2-9x-((7x^2-10x))=0


We calculate terms in parentheses: -((7x^2-10x)), so:

(7x^2-10x)

We get rid of parentheses

7x^2-10x

Back to the equation:

-(7x^2-10x)


We get rid of parentheses

3x^2-7x^2-9x+10x=0

We add all the numbers together, and all the variables

-4x^2+x=0

a = -4; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-4)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-4}=\frac{-2}{-8}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-4}=\frac{0}{-8}
=0
$